The Collatz Conjecture: The Simplest Problem Nobody Can Solve
Pick any positive integer. If it’s even, halve it. If it’s odd, triple it and add one. Repeat. You’ll always end up at 1.
That’s the Collatz Conjecture. It sounds like something you could prove in an afternoon. Mathematicians have been trying for nearly 90 years. Nobody’s succeeded.
You might also hear it called the 3n+1 problem, Ulam’s conjecture, Kakutani’s problem, Thwaites conjecture, Hasse’s algorithm, or the Syracuse problem. Same puzzle, different names.
The Conjecture
The rules are dead simple:
- Start with any positive integer \( n \).
- If \( n \) is even, divide by 2 to get \( n/2 \).
- If \( n \) is odd, multiply by 3 and add 1 to get \( 3n + 1 \).
- Repeat until you hit 1.
The conjecture claims every positive integer eventually reaches 1. No exceptions.
Quick Examples
Starting with 1: Already there. Done.
Starting with 2 (even): \( 2 \to 1 \). One step.
Starting with 3 (odd): \( 3 \to 10 \to 5 \to 16 \to 8 \to 4 \to 2 \to 1 \). Seven steps.
Starting with 27: This one’s wild. It takes 111 steps and climbs as high as 9,232 before finally dropping to 1.
The Formal Definition
Mathematically, we define the Collatz function \( f: \mathbb{Z}^+ \to \mathbb{Z}^+ \) as:
$$f(n) = \begin{cases} n/2 & \text{if } n \equiv 0 \pmod{2} \\ 3n + 1 & \text{if } n \equiv 1 \pmod{2} \end{cases}$$
The conjecture states that for every positive integer \( n \), repeated application of \( f \) eventually yields 1. In other words, the sequence \( n, f(n), f(f(n)), \ldots \) always terminates at 1.
Why It’s So Hard
The problem looks innocent. It’s not.
The 3n+1 step makes odd numbers grow. The n/2 step makes even numbers shrink. But there’s no obvious pattern to how these compete. Sometimes numbers explode upward before crashing down. Sometimes they bounce around for hundreds of steps.
Paul Erdős, one of the greatest mathematicians of the 20th century, said: “Mathematics may not be ready for such problems.”
The conjecture has been verified by computer for all numbers up to approximately \( 2.95 \times 10^{20} \) (Christian Hercher and David Barina’s distributed computing work, 2020). Every single one reaches 1. But verification isn’t proof. There could be a counterexample hiding somewhere larger. This is the same gap between computation and proof that makes prime number formulas so elusive.
The Stopping Time
The stopping time of \( n \) is how many steps it takes to reach 1. Some numbers have surprisingly long stopping times relative to their size.
The number 27 takes 111 steps. The number 9,780,657,630 takes 1,132 steps. There’s no formula to predict stopping time from the starting number.
In September 2019, Terence Tao proved that “almost all” Collatz orbits attain almost bounded values. Published in Forum of Mathematics, Pi (2020), this was the most significant partial result in the conjecture’s history. For any function \( f(n) \) tending to infinity (however slowly), the set of starting values whose orbit minimum exceeds \( f(n) \) has logarithmic density zero. But “almost all” isn’t “all.” The conjecture remains open. Tao himself called it merely a “partial result toward the full conjecture.”
What Could Go Wrong?
If the conjecture is false, there are two possibilities:
First, there might be a number whose sequence goes to infinity. It just keeps growing forever, never coming back down.
Second, there might be a cycle that doesn’t include 1. The sequence could loop forever through a set of numbers without ever reaching 1. The only known cycle is \( 1 \to 4 \to 2 \to 1 \), but others might exist.
Nobody has found either type of counterexample. But nobody has proven they can’t exist.
Is It Useless?
Some mathematicians call the Collatz Conjecture a “dangerous” problem because it’s so easy to state, so tempting to attempt, and so impossible to crack.
The conjecture has no known applications to other areas of mathematics. It doesn’t connect to deep theorems or open doors to new territories. In that sense, it’s isolated. Jeffrey Lagarias compiled an annotated bibliography cataloguing over 500 papers on the conjecture (The Ultimate Challenge: The 3x+1 Problem, AMS, 2010). Five hundred papers on a problem with no applications. That tells you something about its pull.
But here’s the thing. We don’t know why we can’t solve it. The techniques that work on other number theory problems (modular arithmetic, analytic methods, algebraic structures) all fail here. The 3n+1 step scrambles the binary representation of numbers in ways that resist systematic analysis. It connects to dynamical systems (iteration of a piecewise-linear map), ergodic theory (mixing properties modulo powers of 2), and even p-adic analysis. Understanding why standard tools fail might teach us something important.
And there’s always the chance that a solution would require entirely new mathematics. That’s happened before. The Weierstrass function forced mathematicians to rebuild the foundations of analysis. The prime number theorem required complex analysis nobody expected. Sometimes the “useless” problems force breakthroughs.
The Hailstone Analogy

Collatz sequences are sometimes called “hailstone numbers” because they rise and fall like hailstones in a cloud. A hailstone gets pushed up by updrafts, falls a bit, gets pushed up again, and eventually drops to the ground.
The analogy is pretty good. Numbers bounce chaotically before eventually settling at 1 (the ground). But unlike real hailstones, we can’t prove all Collatz sequences eventually land.
The distribution of stopping times is itself interesting. On average, the stopping time of \( n \) grows roughly as \( 6.95 \times \log_2(n) \). But individual numbers deviate wildly from this average. The number 27, which takes 111 steps and climbs to 9,232, is a famous outlier for its size. This unpredictability is part of what makes the conjecture so resistant to systematic problem-solving approaches.
Frequently Asked Questions
What is the Collatz Conjecture?
The Collatz Conjecture states that if you take any positive integer, halve it if even or triple it and add one if odd, and keep repeating, you’ll eventually reach 1. Despite being tested on numbers up to 2^68, nobody has proven it’s true for all integers.
Who discovered the Collatz Conjecture?
German mathematician Lothar Collatz proposed it in 1937. But several mathematicians worked on similar problems independently, which is why it has so many names: Ulam’s conjecture (Stanisław Ulam), Kakutani’s problem (Shizuo Kakutani), Thwaites conjecture (Bryan Thwaites), and the Syracuse problem.
Has the Collatz Conjecture been proven?
No. Despite nearly 90 years of effort by professional mathematicians, the conjecture remains unproven. In 2019, Terence Tao proved that “almost all” numbers satisfy a weaker form of the conjecture, but the full statement is still open. It’s considered one of the hardest unsolved problems in mathematics.
What is stopping time in the Collatz sequence?
Stopping time is the number of steps needed to reach 1 from a given starting number. For example, 3 has stopping time 7, while 27 has stopping time 111. There’s no known formula to calculate stopping time without actually running the sequence.
Why is the Collatz Conjecture so difficult?
The difficulty comes from the chaotic interaction between the two rules. The 3n+1 step mixes the binary representation of numbers in unpredictable ways. Standard number theory tools (modular arithmetic, analytic methods) don’t gain traction. Paul Erdős said mathematics “may not be ready” for such problems.
What are hailstone numbers?
Hailstone numbers are another name for Collatz sequences. The name comes from how the numbers rise and fall chaotically, like hailstones bouncing in storm clouds before eventually falling to the ground. The sequence “bounces” up and down before settling at 1.
Could there be a number that never reaches 1?
Possibly. If the conjecture is false, either some number’s sequence goes to infinity, or there’s a cycle that doesn’t include 1. No one has found such a counterexample, but no one has proven one can’t exist. The conjecture has been verified computationally up to about 2^68.
Is there a prize for solving the Collatz Conjecture?
Paul Erdős offered $500 for a solution, which was substantial for him. Various institutions and individuals have offered bounties over the years. But the real prize would be the mathematical insight required to crack it, which could open new areas of number theory.
Does the Collatz Conjecture have any practical applications?
Not directly. It doesn’t connect to other mathematical theorems or have known real-world applications. Some consider it an “isolated” problem. But attempting to solve it has led to new techniques in dynamical systems and computational number theory that have broader value.
What did Terence Tao prove about Collatz in 2019?
Tao proved that “almost all” Collatz orbits attain almost bounded values. In technical terms, for any function f(n) going to infinity (however slowly), almost all starting values eventually drop below f(n). This is the strongest result to date, but it doesn’t prove the full conjecture since “almost all” excludes potentially infinitely many exceptions.