Some times ago they added the Trinity College Notebook by Isaac Newton, which he used to teach in the college in 17th century.

List of other works of Newton can be found at www.newton.ac.uk/newton.html.

Feel free to ask questions, send feedback and even point out mistakes. Great conversations start with just a single word. How to write better comments?
1. fractad says:

Thanks so much for linking to this. It’s like going back in time to listen to Newton himself. When I was 13 years old, my father had a sabbatical in Cambridge for 6 months, and I remember walking over a wooden bridge designed by Newton that did not use use any bolts to hold it together. Years later they took it apart to replace some rotted pieces, and they couldn’t put it back together they way he had constructed it. What a genius.

1. Gaurav Tiwari says:

Thanks for your reply @fractad. It is really good to read and write about genius like Newton. Thanks for you info about the bridge designed by Newton. That must be fantastic experience. I didn’t know it.

This site uses Akismet to reduce spam. Learn how your comment data is processed.

## 5 Tips for Self-Publishing Success

The named publishers are nowadays suffering because they tend to promote a few books by even fewer celebrity authors. This leads to serious financial problems, such as when they give a famous politician a major cash advance and that person’s book fails to sell. The issue is compounded by publishers aiming for the widest possible audience while the audience is…

## Dirichlet’s Theorem and Liouville’s Extension of Dirichlet’s Theorem

Topic Beta & Gamma functions Statement of Dirichlet’s Theorem $\int \int \int_{V} x^{l-1} y^{m-1} z^{n-1} dx dy ,dz = \frac { \Gamma {(l)} \Gamma {(m)} \Gamma {(n)} }{ \Gamma{(l+m+n+1)} }$ , where V is the region given by $x \ge 0 y \ge 0 z \ge 0 x+y+z \le 1$ . Brief Theory on Gamma and…

## Smart Fallacies: i=1, 1= 2 and 1= 3

This mathematical fallacy is due to a simple assumption, that $-1=\dfrac{-1}{1}=\dfrac{1}{-1}$ . Proceeding with $\dfrac{-1}{1}=\dfrac{1}{-1}$ and taking square-roots of both sides, we get: $\dfrac{\sqrt{-1}}{\sqrt{1}}=\dfrac{\sqrt{1}}{\sqrt{-1}}$ Now, as the Euler’s constant $i= \sqrt{-1}$ and $\sqrt{1}=1$ , we can have $\dfrac{i}{1}=\dfrac{1}{i} \ldots \{1 \}$ $\Rightarrow i^2=1 \ldots \{2 \}$ . This is complete contradiction to the…

## Solving Integral Equations – (1) Definitions and Types

If you have finished your course in Calculus and Differential Equations, you should head to your next milestone: the Integral Equations. This marathon series (planned to be of 6 or 8 parts) is dedicated to interactive learning of integral equations for the beginners —starting with just definitions and demos —and the pros— taking it to the heights of problem solving.…